(1/8)^2x-3=16^x+1

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Solution for (1/8)^2x-3=16^x+1 equation: 



(1/8)^2x-3=16^x+1

We move all terms to the left:

(1/8)^2x-3-(16^x+1)=0



Domain of the equation: 8)^2x!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

(+1/8)^2x-(16^x+1)-3=0

We get rid of parentheses

(+1/8)^2x-16^x-1-3=0

We multiply all the terms by the denominator


(+1-16^x*8)^2x-1*8)^2x-3*8)^2x=0

Wy multiply elements

-64x^2+(+1-16^x*8)^2x=0

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